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Derivative as slope of a tangent line | Taking derivatives | Differential Calculus | Khan Academy

2 Views· 04/01/24
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Courses on Khan Academy are always 100% free. Start practicing—and saving your progress—now: https://www.khanacademy.org/ma....th/ap-calculus-ab/ab

Understanding that the derivative is just the slope of a curve at a point (or the slope of the tangent line)

Practice this yourself on Khan Academy right now: https://www.khanacademy.org/e/skill-check--tangent-lines?utm_source=YTdescription&utm_medium=YTdescription&utm_campaign=YTdescription

Watch the next lesson: https://www.khanacademy.org/math/differential-calculus/taking-derivatives/derivative_intro/v/tangent-slope-as-limiting-value-of-secant-slope-example-1?utm_source=YT&utm_medium=Desc&utm_campaign=DifferentialCalculus

Missed the previous lesson?
https://www.khanacademy.org/math/differential-calculus/taking-derivatives/secant-line-slope-tangent/v/approximating-equation-of-tangent-line-word-problem-1?utm_source=YT&utm_medium=Desc&utm_campaign=DifferentialCalculus

Differential calculus on Khan Academy: Limit introduction, squeeze theorem, and epsilon-delta definition of limits.

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